SIMPLE STRESS AND STRAIN
SIMPLE STRESS AND STRAIN
STRESS:
STRESS IS THE INTERNAL RESISTANCE OFFERED BY THE BODY TO
DEFORMATION.
STRESS IS USUALLY MEASURED BY THE INTENSITY OF FORCE PER UNIT
AREA.
STRESS = P/A
WHERE P= FORCE
A= AREA OF
CROSS SECTION
UNIT OF STRESS: N/m2 ,KN/m2 ,N/mm2
WHY STRESS IS EQUAL TO FORCE/AREA?
DID YOU THOUGHT ABOUT IT WHY STRESS IS FORCE/AREA,DON'T WORRY I'LL EXPLAIN,THERE ARE SOME ASSUMPTIONS AND THEY ARE
DID YOU THOUGHT ABOUT IT WHY STRESS IS FORCE/AREA,DON'T WORRY I'LL EXPLAIN,THERE ARE SOME ASSUMPTIONS AND THEY ARE
- THE OBJECT IS HOMOGENEOUS
- THE OBJECT IS ISOTROPIC AND
- THE OBJECT ACTS AS A SINGLE MEMBER AND NOT AS LAYERS.
NOW, 10X = 10KN ( HERE X= UNIT AREA )
1X = ?
FOR LOAD APPLIED ON UNIT AREA BY CROSS MULTIPLYING WE GET = 1X * 10KN /10X = 1KN
THEREFORE STRESS IS EQUAL TO THE LOAD APPLIED ON UNIT AREA.
TYPE OF STRESSES:
1.
DIRECT STRESSES
2.
SHEAR STRESS/ TANGENTIAL STRESS
3.
BENDING STRESS
4.
TORSIONAL STRESS
1) DIRECT STRESS /NORMAL STRESS:
THE STRESS DUE TO AN
AXIAL FORCE .IT MAY BE EITHER TENSILE OR COMPRESSIVE.
2) SHEAR STRESS:
WHEN THE TWO PARTS
EXERT EQUAL AND OPPOSITE FORCE ON EACH OTHER LATERALLY IN A DIRECTION
TANGENTIAL TO THEIR SURFACE IN CONTACT, IT IS CALLED TANGENTIAL FORCE. SHEAR
STRESS IS THE TANGENTIAL FORCE PER UNIT AREA.
3) BENDING STRESS(FLEXURAL STRESS):
BENDING STRESS IS DUE TO TRANSVERSE LOADS."IN THE ELEMENT
SHOWN, THE LAYERS ABOVE N.A ARE SUBJECTED TO FLEXURAL" COMPRESSIVE STRESS
AND THE LAYERS BELOW NA ARE SUBJECTED TO FLEXURAL TENSILE STRESS.
BENDING STRESS = M/Z
WHERE M = BENDING MOMENT
Z = SECTION MODULUS
4) TORSIONAL STRESS:
TWISTING MOMENT RESULTS IN SHEAR STRESS KNOWN AS TORSIONAL
STRESS.
TORSIONAL STRESS = T/ZP
WHERE T = TWISTING MOMENT
ZP
= TORSIONAL SECTIONAL MODULUS
STRAIN:
STRAIN IS THE MEASURE OF DEFORMATION CAUSED DUE TO EXTERNAL LOADING.
STRAIN = ΔL /L
WHERE ΔL = CHANGE
IN LENGTH
L =
ORIGINAL LENGTH
TYPES OF STRAIN:
1. LONGITUDINAL STRAIN:
THE DEFORMATION CAUSED BY NORMAL/DIRECT FORCE IN ITS DIRECTION .IF STRESS IS TENSILE, IT IS CALLED TENSILE STRAIN AND IF STRESS IS COMPRESSIVE, IT IS CALLED COMPRESSIVE STRAIN.
THE DEFORMATION CAUSED BY NORMAL/DIRECT FORCE IN ITS DIRECTION .IF STRESS IS TENSILE, IT IS CALLED TENSILE STRAIN AND IF STRESS IS COMPRESSIVE, IT IS CALLED COMPRESSIVE STRAIN.
2. SHEAR STRAIN:
IF THE STRESS IS SHEAR, THE CORRESPONDING STRAIN IS KNOWN AS SHEAR STRAIN. IT IS CHANGE IN ANGLE MEASURED IN RADIANS.
IF THE STRESS IS SHEAR, THE CORRESPONDING STRAIN IS KNOWN AS SHEAR STRAIN. IT IS CHANGE IN ANGLE MEASURED IN RADIANS.
3. VOLUMETRIC STRAIN:
IT IS THE RATIO OF CHANGE IN VOLUME TO THE ORIGINAL VOLUME.
IT IS THE RATIO OF CHANGE IN VOLUME TO THE ORIGINAL VOLUME.
THE BASIC RELATION IS WHEN A EXTERNAL LOAD IS APPLIED STRESS IS PRODUCED AND DUE TO STRESS, STRAIN OCCURS IN THIS WITHOUT EXTERNAL LOAD THERE IS NO STRAIN RIGHT.
BUT I THINK ITS A MISCONCEPTION BECAUSE WHEN A METAL SHAFT IS SUBJECTED TO EXCESSIVE HEATING THE METAL SHAFT STARTS TO EXTEND(DEFORM) DUE TO THE HEATING BUT HERE WE DIDN'T APPLIED A LOAD SO FROM WHERE THE STRAIN IS PRODUCED.
BUT I THINK ITS A MISCONCEPTION BECAUSE WHEN A METAL SHAFT IS SUBJECTED TO EXCESSIVE HEATING THE METAL SHAFT STARTS TO EXTEND(DEFORM) DUE TO THE HEATING BUT HERE WE DIDN'T APPLIED A LOAD SO FROM WHERE THE STRAIN IS PRODUCED.
SO HERE WITHOUT LOAD ALSO THE STRESS CAN BE PRODUCED AND IF THERE IS STRAIN THEN DEFINITELY THERE WILL BE STRESS BUT NOT VICE-VERSA.IN THE ABOVE EXAMPLE WHEN WE RESTRICT THE EXTENSION OF SHAFT THERE WILL BE STRESS BUT NO STRAIN.
HOOK'S LAW :
"HOOK'S LAW STATES THAT WITHIN THE ELASTIC LIMITS, STRESS
IS PROPORTIONAL TO STRAIN."
STRESS α STRAIN
STRESS
= CONSTANT X STRAIN
"CONSTANT IS CALLED MODULUS OF ELASTICITY ( E )"
E =
STRESS/STRAIN
PROPORTIONALITY LIMIT:
"THE STRAIGHT LINE FROM O TO A REPRESENTS EXTENSION
PROPORTIONAL TO THE LOAD . IT IS THE LIMIT, THAT EXTENSIONS CEASE TO BE PROPORTIONAL
TO THE CORRESPONDING STRESSES. HOOK 'S LAW IS VALID UPTO LIMIT OF
PROPORTIONALITY.
ELASTIC LIMIT:
IT IS THE MAXIMUM STRESS THAT MAY BE DEVELOPED WITH NO PERMANENT
/ RESIDUAL DEFORMATION AFTER THE REMOVAL
OF LOAD .
YIELD POINT:
"IF THE MATERIAL IS LOADED BEYOND THE ELASTIC LIMIT,
ELONGATION OR YIELDING OF MATERIAL TAKES
PLACE WITHOUT ANY CORRESPONDING INCREASE OF LOAD. IT IS CALLED UPPER YIELD
POINT.
ELASTIC RANGE:
IT IS THE REGION OF THE STRESS-STRAIN CURVE BETWEEN THE ORIGIN TO THE ELASTIC LIMIT.
IT IS THE REGION OF THE STRESS-STRAIN CURVE BETWEEN THE ORIGIN TO THE ELASTIC LIMIT.
PLASTIC RANGE:
IT IS THE REGION OF THE STRESS-STRAIN CURVE BETWEEN THE ELASTIC
LIMIT AND THE POINT OF RUPTURE.
STRAIN HARDENING:
FROM THE POINT ‘D’ TO 'E' IN THE GRAPH ,THE PLASTIC DEFORMATION
INCREASES WITHOUT ANY INCREASE IN THE STRESS .DUE TO THE PLASTIC REARRANGEMENT
OF PARTICLES IN THE MATERIAL, RESISTANCE TO THE STRESS INCREASES.
ULTIMATE STRENGTH:
IT CORRESPONDS TO THE HIGHEST POINT OF THE STRESS STRAIN CURVE.
ULTIMATE STRESS = MAXIMUM LOAD/ ORIGINAL AREA OF CROSS SECTION
UPTO MAXIMUM LOAD , BARS
EXTENDS UNIFORMLY OVER ITS LENGTH ,BUT IF STRESS CONTINUES, A LOCAL REDUCTION
IN CROSS SECTION OCCURS LEADING TO THE FORMATION OF NECK ZONE."
RUPTURE STRENGTH:
THE RUPTURE STRENGTH IS THE STRESS CORRESPONDING TO THAT AT
FAILURE. THE RUPTURE STRENGTH (REPRESENTED BY F) IS LOWER THAN THE ULTIMATE
STRENGTH BECAUSE RUPTURE STRENGTH IS CALCULATED BY THE FAILURE LOAD DIVIDED BY
ORIGINAL CROSS SECTION AREA.
ACTUALLY DUE TO NECK FORMATION, CROSS SECTIONAL AREA DECREASES
AND THE ACTUAL RUPTURE STRENGTH IS MUCH HIGHER THAN NOMINAL RUPTURE STRENGTH.
NOMINAL STRESS: IT IS THE STRESS CORRESPONDING TO THE ORIGINAL
CROSS SECTIONAL AREA .
ACTUAL OR TRUE STRESS: IT IS THE STRESS BASED ON ACTUAL AREA OF
THE NECKED PORTION .
STRESS-STRAIN CURVE FOR HIGH YIELD DEFORMED BARS:
FOR TORSTEEL AND ALUMINIUM WITH NO WELL DEFINED YIELD
POINT, THE YIELD STRENGTH IS DETERMINED BY OFFSET METHOD. A LINE OFFSET OF 0.2%
OF STRAIN IS DRAWN PARALLEL TO THE IN INITIAL LINEAR PART OF THE CURVE. THE
POINT OF INTERSECTION OF THE LINE WITH THE CURVE CORRESPONDS TO THE YIELD
STRENGTH OF THE MATERIAL.
GAUGE LENGTH AND PERCENTAGE ELONGATION:
GAUGE LENGTH:
IT IS THE LENGTH OF TEST PIECE OVER WHICH EXTENSIONS ARE
MEASURED IT IS A FUNCTION OF THE CROSS-SECTIONAL AREA OR THE DIAMETER OF THE
TEST BAR.
GAUGE LENGTH = 5.65(a1/2)
PERCENTAGE ELONGATION:
IT IS THE PERCENTAGE INCREASE IN LENGTH OF THE GAUGE-LENGTH.
PERCENTAGE ELONGATION = [
FINAL LENGTH- ORIGINAL LENGTH /ORIGINAL LENGTH ]X 100
POISSON’S RATIO:
THE RATIO OF LATERAL STRAIN TO LONGITUDINAL STRAIN IS CALLED
POISSON'S RATIO. THE RATIO IS CONSTANT FOR A GIVEN MATERIAL.
POISSON'S RATIO (µ) = LATERAL STRAIN / LONGITUDINAL STRAIN
THE VALUE LIES BETWEEN 0.25 TO 0.34 FOR MOST OF THE METALS .
THE MAXIMUM POSSIBLE VALUE OF POISSON’S RATIO IS 0.5.
FOR AN IDEAL ELASTIC IN-COMPRESSIBLE MATERIAL WHOSE VOLUMETRIC
STRAIN IS ZERO
POISSON'S RATIO FOR IMPORTANT MATERIALS :
CORK = 0,
CAST IRON = 0.2 TO
0.3, BRASS =
0.34,
CONCRETE = 0.1 TO 0.2, STEEL = 0.27 TO 0.3, GOLD = 0.44
GLASS = 0.2 TO 0.27, ALUMINIUM = 0.33
CONCRETE = 0.1 TO 0.2, STEEL = 0.27 TO 0.3, GOLD = 0.44
GLASS = 0.2 TO 0.27, ALUMINIUM = 0.33
INCOMPRESSIBLE MATERIALS, CLAY, PARAFFIN AND RUBBER = 0.5
ELASTIC CONSTANTS :
1) YOUNG’S MODULUS (OR) MODULUS OF ELASTICITY (E) :
RATIO OF DIRECT STRESS TO DIRECT STRAIN WITHIN LIMIT OF
PROPORTIONALITY IS CALLED YOUNG’S MODULUS.
FOR, STEEL - 200 GPA ALUMINIUM - 70 GPA COPPER - 120 GPA
DIAMOND - 1200 GPA BRASS - 100 GPA BRONZE - 80 GPA
DIAMOND - 1200 GPA BRASS - 100 GPA BRONZE - 80 GPA
2)MODULUS OF RIGIDITY(G):
RATIO OF SHEAR STRESS TO SHEAR STRAIN IS CALLED MODULUS OF
RIGIDITY.
3)BULK MODULUS ( K ) :
RATIO OF DIRECT STRESS TO VOLUMETRIC STRAIN IS CALLED BULK
MODULUS.
RELATION BETWEEN ELASTIC CONSTANTS :
E =2G( 1 + µ) E = 3K(1 - 2µ)
E = 9KG/(3K + G) µ = (3K + 2G) / (6K + 2G)
STRESSES AND DEFORMATIONS:
l) BARS OF UNIFORM CROSS
SECTION:
THE TOTAL EXTENSION 'Δ' OF THE BAR AB WILL BE GIVEN BY
Δ = Δ1 + Δ2 + Δ3
= P(L1 +L2 +L3)/AE
ll) BARS OF VARYING CROSS SECTION:
= P(L1 +L2 +L3)/AE
ll) BARS OF VARYING CROSS SECTION:
Δ = Δ1 + Δ2 + Δ3
= P/E(L1/A1+L2/A2
+L3/A3)
TEMPERATURE STRESSES :
WHEN TEMPERATURE OF A MATERIAL CHANGES, THERE WILL BE CHANGE IN
DIMENSIONS. IF THESE CHANGES ARE PREVENTED, NO CHANGE IN LENGTH IS PERMISSIBLE
AND STRESS ARE DEVELOPED IN THE MATERIAL. THESE STRESSES ARE KNOWN AS
TEMPERATURE STRESS.
1) BAR OF UNIFORM SECTION:
IF THE TEMPERATURE IS INCREASED THROUGH T0, THE BAR
WILL BE INCREASED IN LENGTH BY AN AMOUNT
Δ = L α T [·:
Α = CO-EFFICIENT OF THERMAL EXPANSION]
Δ = PL/E
WHERE P = TEMPERATURE
STRESS
P = ΔE/L
= L α T. E/L
P =αTE
WHEN THE ENDS YIELD BY AN AMOUNT ‘a’ , THE TOTAL AMOUNT OF
DEFORMATION CHECKED IS (Δ – a)
P =(Δ – a)E/L
2) BAR OF COMPOSITE SECTION :
LET US CONSIDER A BAR CONSIST OF TWO DIFFERENT METAL BARS ‘A’ AND ‘B’:
LET US CONSIDER A BAR CONSIST OF TWO DIFFERENT METAL BARS ‘A’ AND ‘B’:
αA - COEFFICIENT OF LINEAR EXPANSION IN BAR A
αB - COEFFICIENT OF LINEAR EXPANSION IN BAR B
IF αA
< αB
DUE TO TEMPERATURE FALL, BAR A – TENSION
BAR B - COMPRESSION
DUE TO TEMPERATURE RISE, BAR A - COMPRESSION
BAR B - TENSION
STRAIN ENERGY:
IF THE ELASTIC LIMIT IS NOT EXCEEDED, THE WORKDONE IN STRAINING
THE MATERIAL IS STORED IN IT IN THE FORM OF STRAIN ENERGY. IT IS ALSO CALLED “RESILIENCE".
ENERGY STORED = (P.A.E.L)/2
U = (1/2) X STRESS X STRAIN X VOLUME
U = (P2/2E) X VOLUME
STRAIN ENERGY IS ALWAYS A POSITIVE SCALAR QUANTITY.
PROOF RESILIENCE (UP):
THE STRAIN ENERGY STORED
AT PROPORTIONALITY LIMIT IS CALLED PROOF RESILIENCE.
UP = (σ2/2E)
X V
MODULUS OF RESILIENCE:
THE PROOF RESILIENCE PER UNIT VOLUME. IT IS THE PROPERTY OF
MATERIAL.
MODULUS OF RESILIENCE = σ2/2E
STRAIN ENERGY DUE TO DIFFERENT TYPES OF LOADING:
A) GRADUAL LOADING:
LET THE AXIAL LOAD 'P' BE APPLIED GRADUALLY TO A BAR AND 'Δ' BE THE
CORRESPONDING DEFORMATION AND 'R' BE THE TOTAL RESISTANCE SETUP OF THE BODY.
WORKDONE BY THE EXTERNAL LOAD = ½ X PΔ
WORKDONE IN THE BODY = ½ x σAΔ
WORKDONE IN THE BODY = ½ x σAΔ
EQUATING THE WORK STORED TO THE WORKDONE WE GET, σ = P/A
THUS, THE MAXIMUM STRESS SETUP IS EQUAL TO LOAD DIVIDED BY AREA
OF SECTION OF THE BAR.
B) SUDDEN LOADING:
IF LOAD 'P' IS APPLIED SUDDENLY, THE DEFORMATION INCREASES FROM ZERO VALUE TO ITS FINAL VALUE 'Δ'.
IF LOAD 'P' IS APPLIED SUDDENLY, THE DEFORMATION INCREASES FROM ZERO VALUE TO ITS FINAL VALUE 'Δ'.
HENCE, THE WORKDONE ON THE BAR = PΔ
THE WORK STORED = ½ x σAΔ
EQUATING THE WORK STORED TO THE WORK SUPPLIED, σ = 2P/A
THUS, THE MAXIMUM STRESS SETUP IN THE BODY IN THIS CASE IS TWICE
THAT IN CASE OF GRADUAL LOADING.
C) IMPACT LOADING:
σ = P/A[1+(1+2Eah/PL)1/2]
HOWEVER, IF Δ IS NEGLIGIBLE COMPARED TO h,
THEN WE HAVE
PH = σ2AL/2E
NOTE : DUE TO STATIC LOADING, STRESS IS
INDEPENDENT OF E.
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